选择后提交新页面的代码

2009-12-13 15:46:04 by 【6yang】, 65 visits, 收藏 | 返回
 <script language="JavaScript">
function surfto(form){
var myindex=form.dest.selectedIndex;
window.open(form.dest.options[myindex].value,"_blank");}
</SCRIPT><form   NAME="myform" >
          <select name="dest" id=leftSelectBoxGlobal style="DISPLAY: none; WIDTH:225px; HEIGHT:22px;"  class="select">
              <option>上海6yang互联网1</option><option value='http://www.6yang.net'>上海6yang互联网2</option><option value='http://www.6yang.net'>上海6yang互联网3</option><option value='http://www.6yang.net'>上海6yang互联网4</option><option value='http://www.6yang.net'>上海6yang互联网5</option></select>
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